Linear Algebra Examples

$3800 + 585 \log_{2} (x)$

Step 1

Find the asymptotes.

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Step 1.1

Find where the expression $3800 + \log_{2} (x^{585})$ is undefined.

$x \leq 0$

Step 1.2

Since $3800 + \log_{2} (x^{585})$ $\to$ $\infty$ as $x$ $\to$ $0$ from the left and $3800 + \log_{2} (x^{585})$ $\to$ $\infty$ as $x$ $\to$ $0$ from the right, then $x = 0$ is a vertical asymptote.

$x = 0$

Step 1.3

Ignoring the logarithm, consider the rational function $R (x) = \frac{a x^{n}}{b x^{m}}$ where $n$ is the degree of the numerator and $m$ is the degree of the denominator.

1. If $n < m$ , then the x-axis, $y = 0$ , is the horizontal asymptote.

2. If $n = m$ , then the horizontal asymptote is the line $y = \frac{a}{b}$ .

3. If $n > m$ , then there is no horizontal asymptote (there is an oblique asymptote).

Step 1.4

There are no horizontal asymptotes because $Q (x)$ is $1$ .

No Horizontal Asymptotes

Step 1.5

No oblique asymptotes are present for logarithmic and trigonometric functions.

No Oblique Asymptotes

Step 1.6

This is the set of all asymptotes.

Vertical Asymptotes: $x = 0$

No Horizontal Asymptotes

Vertical Asymptotes: $x = 0$

No Horizontal Asymptotes

Step 2

Find the point at $x = 1$ .

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Step 2.1

Replace the variable $x$ with $1$ in the expression.

$f (1) = 3800 + 585 \log_{2} (1)$

Step 2.2

Simplify the result.

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Step 2.2.1

Simplify each term.

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Step 2.2.1.1

Logarithm base $2$ of $1$ is $0$ .

$f (1) = 3800 + 585 \cdot 0$

Step 2.2.1.2

Multiply $585$ by $0$ .

$f (1) = 3800 + 0$

Step 2.2.2

Add $3800$ and $0$ .

$f (1) = 3800$

Step 2.2.3

The final answer is $3800$ .

$3800$

Step 2.3

Convert $3800$ to decimal.

$y = 3800$

Step 3

Find the point at $x = 2$ .

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Step 3.1

Replace the variable $x$ with $2$ in the expression.

$f (2) = 3800 + 585 \log_{2} (2)$

Step 3.2

Simplify the result.

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Step 3.2.1

Simplify each term.

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Step 3.2.1.1

Logarithm base $2$ of $2$ is $1$ .

$f (2) = 3800 + 585 \cdot 1$

Step 3.2.1.2

Multiply $585$ by $1$ .

$f (2) = 3800 + 585$

Step 3.2.2

Add $3800$ and $585$ .

$f (2) = 4385$

Step 3.2.3

The final answer is $4385$ .

$4385$

Step 3.3

Convert $4385$ to decimal.

$y = 4385$

Step 4

Find the point at $x = 4$ .

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Step 4.1

Replace the variable $x$ with $4$ in the expression.

$f (4) = 3800 + 585 \log_{2} (4)$

Step 4.2

Simplify the result.

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Step 4.2.1

Simplify each term.

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Step 4.2.1.1

Logarithm base $2$ of $4$ is $2$ .

$f (4) = 3800 + 585 \cdot 2$

Step 4.2.1.2

Multiply $585$ by $2$ .

$f (4) = 3800 + 1170$

Step 4.2.2

Add $3800$ and $1170$ .

$f (4) = 4970$

Step 4.2.3

The final answer is $4970$ .

$4970$

Step 4.3

Convert $4970$ to decimal.

$y = 4970$

Step 5

The log function can be graphed using the vertical asymptote at $x = 0$ and the points $(1, 3800), (2, 4385), (4, 4970)$ .

Vertical Asymptote: $x = 0$

$\begin{array}{c} x & y \\ 1 & 3800 \\ 2 & 4385 \\ 4 & 4970 \end{array}$

Step 6